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Help out a company with bad security practices to validate their passwords with Excel!
You are given the following requirements:
– At least six characters long
– No spaces
– At least one number
– At least one special character
Drop your solution in the comments below 🙂
Our solution:
=IF(AND(LEN(F4)>=6;NOT(ISNUMBER(SEARCH(” “;F4)));
COUNT(FIND({0;1;2;3;4;5;6;7;8;9};F4))>0;
COUNT(FIND($K$4:$K$16;F4))>0);”Valid”;”Invalid”)
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Emil har jobbat på Learnesy som produktutvecklare i flera år och ligger bakom flera av Learnesys kurser. Han har en utbildning inom datavetenskap med ett stort intresse för det analytiska och teoretiska. Utöver Finska och Svenska snackar Emil även flytande Excelfunktioner!
Inte den snyggaste lösningen, men den funkar. Måste finnas ett bättre sätt än mitt…..
=AND(LEN(F4)>=6;ISERR(NOT(SEARCH(” “;F4)>0));
OR(IFERROR(SEARCH(0;F4)>0;FALSE);
IFERROR(SEARCH(1;F4)>0;FALSE);
IFERROR(SEARCH(2;F4)>0;FALSE);
IFERROR(SEARCH(3;F4)>0;FALSE);
IFERROR(SEARCH(4;F4)>0;FALSE);
IFERROR(SEARCH(5;F4)>0;FALSE);
IFERROR(SEARCH(6;F4)>0;FALSE);
IFERROR(SEARCH(7;F4)>0;FALSE);
IFERROR(SEARCH(8;F4)>0;FALSE);
IFERROR(SEARCH(9;F4)>0;FALSE));
OR(IFERROR(FIND(“!”;F4)>0;FALSE);
IFERROR(FIND(“@”;F4)>0;FALSE);
IFERROR(FIND(“#”;F4)>0;FALSE);
IFERROR(FIND(“$”;F4)>0;FALSE);
IFERROR(FIND(“&”;F4)>0;FALSE)
;IFERROR(FIND(“/”;F4)>0;FALSE);
IFERROR(FIND(“£”;F4)>0;FALSE);
IFERROR(FIND(“$”;F4)>0;FALSE);
IFERROR(FIND(“(“;F4)>0;FALSE);
IFERROR(FIND(“)”;F4)>0;FALSE);
IFERROR(FIND(“{“;F4)>0;FALSE);
IFERROR(FIND(“}”;F4)>0;FALSE);
IFERROR(FIND(“%”;F4)>0;FALSE)))
=IF(AND(LEN(F4)>=6;ISERROR(FIND(” “;F4));
OR(INDEX(ISERROR(MID(F4;SEQUENCE(1;LEN(F4);1;1);1)+0)=FALSE;0));
OR(INDEX(COUNTIF($K$4:$K$16;MID(F4;SEQUENCE(1;LEN(F4);1;1);1))
>0;0)));”Valid”;”Invalid”)
Nice one Fredrik!